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Formulas/maths/Circles/Chord of Contact

Chord of Contact

Equation of the chord joining the two points of tangency when tangents are drawn from external point (x₁, y₁) to circle S = 0. Same form as the tangent at a point — context distinguishes the two.
Derivation

Let P(x1,y1)P(x_1, y_1) be an external point and A(x2,y2)A(x_2, y_2), B(x3,y3)B(x_3, y_3) the two points of tangency on circle Sx2+y2+2gx+2fy+c=0S \equiv x^2 + y^2 + 2gx + 2fy + c = 0.

The tangent at A(x2,y2)A(x_2, y_2) is:

xx2+yy2+g(x+x2)+f(y+y2)+c=0xx_2 + yy_2 + g(x + x_2) + f(y + y_2) + c = 0

Since this tangent passes through P(x1,y1)P(x_1, y_1):

x1x2+y1y2+g(x1+x2)+f(y1+y2)+c=0(1)x_1 x_2 + y_1 y_2 + g(x_1 + x_2) + f(y_1 + y_2) + c = 0 \quad \cdots (1)

Similarly, the tangent at B(x3,y3)B(x_3, y_3) passes through PP:

x1x3+y1y3+g(x1+x3)+f(y1+y3)+c=0(2)x_1 x_3 + y_1 y_3 + g(x_1 + x_3) + f(y_1 + y_3) + c = 0 \quad \cdots (2)

Both equations (1) and (2) say that (x2,y2)(x_2, y_2) and (x3,y3)(x_3, y_3) satisfy the single linear equation:

xx1+yy1+g(x+x1)+f(y+y1)+c=0xx_1 + yy_1 + g(x + x_1) + f(y + y_1) + c = 0

This is the chord of contact — the unique line passing through both contact points AA and BB.

Observation: The chord of contact has exactly the same algebraic form as the tangent at a point. The distinction is contextual: if (x1,y1)(x_1, y_1) lies on the circle, the equation is a tangent; if (x1,y1)(x_1, y_1) is external, the same expression gives the chord of contact.