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Formulas/maths/Hyperbola/Eccentricity

Eccentricity

Eccentricity of a hyperbola is always greater than 1. e = √2 for a rectangular hyperbola (a = b). e → 1⁺ gives a very elongated hyperbola; e → ∞ gives one approaching a pair of lines. Directrices at x = ±a/e (between vertices and centre).
Derivation

By the focus-directrix property, for a point P(x1,y1)P(x_1, y_1) on the right branch of x2/a2y2/b2=1x^2/a^2 - y^2/b^2 = 1 with focus S(c,0)S'(c, 0) and directrix x=a/ex = a/e:

PSPM=e,PS=ex1a,PM=x1ae\frac{PS'}{PM} = e, \quad PS' = ex_1 - a, \quad PM = x_1 - \frac{a}{e} ex1ax1a/e=e(x1a/e)x1a/e=e\frac{ex_1-a}{x_1-a/e} = \frac{e(x_1-a/e)}{x_1-a/e} = e \checkmark

The eccentricity e=c/a=1+b2/a2e = c/a = \sqrt{1+b^2/a^2}.

Since b>0b > 0, we have e>1e > 1 always.

Directrix location: The directrix x=a/ex = a/e lies between the centre and the vertex (a/e<aa/e < a since e>1e > 1) — the opposite of the ellipse, where the directrix lies outside the curve.

Eccentricity of the conjugate hyperbola: For x2/a2y2/b2=1x^2/a^2 - y^2/b^2 = -1 (equivalently y2/b2x2/a2=1y^2/b^2 - x^2/a^2 = 1), eccentricity e2=1+a2/b2=c/be_2 = \sqrt{1+a^2/b^2} = c/b.

The relation 1e12+1e22=1\frac{1}{e_1^2} + \frac{1}{e_2^2} = 1 holds between a hyperbola and its conjugate.