Academy

Focal Radii

For a point P(x₁, y₁) on the right branch (x₁ > 0) of x²/a² − y²/b² = 1: distance to nearer focus S′(c,0) is ex₁ − a, and to farther focus S(−c,0) is ex₁ + a. On the left branch (x₁ < 0), the nearer focus is S(−c,0) and the distances reverse.
Derivation

For x2/a2y2/b2=1x^2/a^2 - y^2/b^2 = 1 with foci S(c,0)S(-c,0) and S(c,0)S'(c,0), directrices x=a/ex = -a/e and x=a/ex = a/e.

Right branch (x1>0x_1 > 0):

Distance to S(c,0)S'(c,0) — using directrix x=a/ex = a/e:

r2=PS=ePM=e ⁣(x1ae)=ex1ar_2 = PS' = e \cdot PM' = e\!\left(x_1 - \frac{a}{e}\right) = ex_1 - a

Distance to S(c,0)S(-c,0) — using directrix x=a/ex = -a/e:

r1=PS=ePM=e ⁣(x1+ae)=ex1+ar_1 = PS = e \cdot PM = e\!\left(x_1 + \frac{a}{e}\right) = ex_1 + a

So r1=ex1+ar_1 = ex_1 + a and r2=ex1ar_2 = ex_1 - a, with r1>r2>0r_1 > r_2 > 0 (since ex1>aex_1 > a on the right branch because x1ax_1 \geq a and e>1e > 1).

Left branch (x1<0x_1 < 0, so x1=x1|x_1| = -x_1):

r1=PS=ex1a,r2=PS=ex1+ar_1 = PS = -ex_1 - a, \quad r_2 = PS' = -ex_1 + a

In all cases, the focal radii are always positive:

rmin=a(e1) at the vertex closer to a focusr_{\min} = a(e-1) \text{ at the vertex closer to a focus} rmax=a(e+1) at the vertex farther from a focusr_{\max} = a(e+1) \text{ at the vertex farther from a focus}