Every non-zero complex number z = r·cis θ has exactly n distinct nth roots. They lie on a circle of radius r^(1/n) centred at the origin, spaced equally at angular intervals of 2π/n — forming a regular n-gon. In Euler form: r^(1/n) · e^(i(θ+2kπ)/n).
Finding the nth roots of a complex number is one of the most geometric results in the chapter. The algebra gives a formula; the geometry reveals why there are exactly n roots and where they sit.
Setup
Let z=reiθ (with r=∣z∣>0 and θ=arg(z)). We want all w such that wn=z.
Write w=ρeiϕ. Then:
wn=ρneinϕ=reiθ
Equating moduli and arguments separately:
ρn=r⟹ρ=r1/n(unique positive real root)
nϕ=θ+2kπ,k∈Z⟹ϕ=nθ+2kπ
The n Distinct Roots
wk=r1/n(cosnθ+2kπ+isinnθ+2kπ),k=0,1,…,n−1
For k≥n, the angle (θ+2kπ)/n differs from some wj with 0≤j≤n−1 by a multiple of 2π — giving the same point. So there are exactly n distinct roots.
The Geometric Picture
All n roots:
- lie on a circle of radius r1/n centred at the origin
- are separated by equal angular gaps of 2π/n
- form the vertices of a regular n-gon
The first root w0=r1/neiθ/n anchors the polygon. Every subsequent root is obtained by rotating w0 by 2π/n.
Special Case: Roots of Unity
When z=1 (r=1, θ=0):
wk=e2πik/n=cosn2kπ+isinn2kπ,k=0,1,…,n−1
A regular n-gon inscribed in the unit circle with one vertex always at (1,0).
Why the Modulus Has a Unique Value
The equation ρn=r with ρ,r>0 has exactly one positive real solution ρ=r1/n. All n roots share this modulus — they lie on a single circle. The only freedom is in the argument, which produces the n distinct angular positions.