The sum of all nth roots of unity is always zero — geometrically, the n equally spaced vectors cancel. The product is (−1)^(n+1): it equals +1 for odd n and −1 for even n. Both follow from Vieta's formulas applied to zⁿ − 1 = 0.
The nth roots of unity are the n solutions of zn=1, equivalently zn−1=0. Their sum and product are determined entirely by the coefficients of this polynomial — no computation needed.
Vieta's Formulas Applied
The polynomial zn−1=0 has roots 1,ω,ω2,…,ωn−1 where ω=e2πi/n.
Written in factored form:
zn−1=(z−1)(z−ω)(z−ω2)⋯(z−ωn−1)
Expanding the right side, the coefficient of zn−1 is −(1+ω+ω2+⋯+ωn−1), and the constant term is (−1)n⋅1⋅ω⋅ω2⋯ωn−1.
Comparing with zn+0⋅zn−1+⋯+0⋅z−1:
Sum (coefficient of zn−1 is 0):
1+ω+ω2+⋯+ωn−1=0
Product (constant term is −1):
1⋅ω⋅ω2⋯ωn−1=(−1)n+1
The product equals +1 for odd n and −1 for even n.
Geometric Confirmation of the Sum
The n roots are equally spaced on the unit circle at angles 0,2π/n,4π/n,…. Their sum as vectors:
k=0∑n−1e2πik/n
By symmetry, this vector sum must point in no particular direction — the only such vector is 0. The algebraic result and the geometric intuition agree.
The Product via Exponents
k=0∏n−1ωk=ω0+1+2+⋯+(n−1)=ωn(n−1)/2=e2πi⋅n(n−1)/(2n)=eiπ(n−1)
=cosπ(n−1)+isinπ(n−1)=(−1)n−1=(−1)n+1
Consistent with Vieta's result. ■
Partial Sums
For any m not divisible by n:
k=0∑n−1ωmk=ωm−1ωmn−1=ωm−11−1=0
This generalisation — the sum of any n equally-spaced points on the unit circle is zero — is used in problems involving selective sums like 1+ω2+ω4+⋯.