Three points are collinear iff the ratio (z₃−z₁)/(z₂−z₁) is real — equivalently, arg((z₃−z₁)/(z₂−z₁)) = 0 or π. The determinant form: the 3×3 determinant with rows (zₖ, z̄ₖ, 1) equals zero. Both forms are used in JEE problems.
Derivation
Three points are collinear when one lies on the line through the other two. In the complex plane, this becomes a condition on arguments — which in turn becomes a condition on a ratio being real.
The Argument Condition
z1, z2, z3 are collinear iff the vector from z1 to z3 points in the same or opposite direction as the vector from z1 to z2.
Same direction: arg(z3−z1)=arg(z2−z1)
Opposite direction: arg(z3−z1)=arg(z2−z1)+π
Both cases are captured by:
arg(z2−z1z3−z1)=0 or π
A complex number has argument 0 or π iff it is real. Therefore:
z1,z2,z3 collinear⟺z2−z1z3−z1∈R
Algebraic Form
A complex number w is real iff w=wˉ. Applying this to the ratio:
z2−z1z3−z1=zˉ2−zˉ1zˉ3−zˉ1
Cross-multiplying:
(z3−z1)(zˉ2−zˉ1)=(zˉ3−zˉ1)(z2−z1)
Expanding and rearranging:
(z3−z1)(zˉ2−zˉ1)−(zˉ3−zˉ1)(z2−z1)=0
Determinant Form
The condition above is equivalent to:
z1z2z3zˉ1zˉ2zˉ3111=0
This is the complex analogue of the Cartesian collinearity determinant x1x2x3y1y2y3111=0. Writing z=x+iy and zˉ=x−iy in each entry, the two determinants differ only by column operations and a constant factor — they contain the same information.
Which Form to Use
Ratio form is faster for problems where you can read off the ratio directly.
Determinant form is better when the three points are given parametrically and you need to eliminate a parameter.