Academy
Formulas/maths/Parabola/Focal Distance

Focal Distance

Distance from any point P(x₁, y₁) on y² = 4ax to the focus S(a, 0). Equals the distance from P to the directrix — the defining property of a parabola.
Derivation

For y2=4axy^2 = 4ax, focus S(a,0)S(a, 0), directrix x=ax = -a.

Let P(x1,y1)P(x_1, y_1) be on the parabola (so y12=4ax1y_1^2 = 4ax_1). The perpendicular from PP to the directrix has foot M(a,y1)M(-a, y_1).

By definition of a parabola:

PS=PM=x1(a)=x1+aPS = PM = x_1 - (-a) = x_1 + a

Therefore the focal distance is simply:

PS=x1+aPS = x_1 + a

Consequences:

  • Since x10x_1 \geq 0 for y2=4axy^2 = 4ax, the minimum focal distance is aa (at the vertex). This minimum is achieved as P(0,0)P \to (0,0).
  • The sum of focal distances from any point is not fixed (unlike an ellipse) — the parabola is the degenerate case of an ellipse with one focus at infinity.
  • For a focal chord with endpoints P1(x1,y1)P_1(x_1, y_1) and P2(x2,y2)P_2(x_2, y_2):
P1S+P2S=(x1+a)+(x2+a)=x1+x2+2aP_1S + P_2S = (x_1 + a) + (x_2 + a) = x_1 + x_2 + 2a