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Work Done in Rotating a Dipole

Work done by external agent rotating dipole from angle θ₁ to θ₂ in a uniform electric field E.
Class 11Class 12
Derivation

Derivation

From the potential energy expression U=−pEcos⁡θU = -pE\cos\theta, the work done by the external agent in rotating the dipole from θ1\theta_1 to θ2\theta_2 equals the change in potential energy:

W=U(θ2)−U(θ1)=(−pEcos⁡θ2)−(−pEcos⁡θ1)W = U(\theta_2) - U(\theta_1) = (-pE\cos\theta_2) - (-pE\cos\theta_1) W=pE(cos⁡θ1−cos⁡θ2)\boxed{W = pE(\cos\theta_1 - \cos\theta_2)}

Interpreting the sign

  • W>0W > 0: external agent does positive work (angle increases, system gains energy)
  • W<0W < 0: field does work (angle decreases toward alignment)

Special cases

From perpendicular to aligned (θ1=90°→θ2=0°\theta_1 = 90° \to \theta_2 = 0°):

W=pE(cos⁡90°−cos⁡0°)=pE(0−1)=−pEW = pE(\cos 90° - \cos 0°) = pE(0 - 1) = -pE

The field does work pEpE; the external agent does −pE-pE.

From aligned to anti-aligned (θ1=0°→θ2=180°\theta_1 = 0° \to \theta_2 = 180°):

W=pE(cos⁡0°−cos⁡180°)=pE(1−(−1))=2pEW = pE(\cos 0° - \cos 180°) = pE(1 - (-1)) = 2pE
Note
Work done depends only on the initial and final angles — not on the path of rotation. This confirms $U = -pE\cos\theta$ is a genuine potential energy.