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Capacitors in Series

In series, same charge Q on each capacitor, voltages add. Equivalent capacitance is always less than the smallest individual capacitance.
Class 11Class 12
Derivation

Charge constraint

In series, the capacitors are connected end-to-end with no branch points between them. The inner plates form isolated conductors. By charge conservation and induction, every capacitor carries the same charge QQ.

Voltage constraint

The total voltage VV across the series combination equals the sum of individual voltages:

V=V1+V2++Vn=QC1+QC2++QCn=Qi=1n1CiV = V_1 + V_2 + \cdots + V_n = \frac{Q}{C_1} + \frac{Q}{C_2} + \cdots + \frac{Q}{C_n} = Q\sum_{i=1}^n \frac{1}{C_i}

Equivalent capacitance

Ceq=QV=1i=1n1CiC_{eq} = \frac{Q}{V} = \frac{1}{\displaystyle\sum_{i=1}^n \frac{1}{C_i}} 1Ceq=1C1+1C2++1Cn\boxed{\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \cdots + \frac{1}{C_n}}

Key property

Ceq<CminC_{eq} < C_{min} — series combination is always less capacitive than the smallest individual capacitor. This is the opposite of resistors in series.

For two capacitors:

Ceq=C1C2C1+C2C_{eq} = \frac{C_1 C_2}{C_1 + C_2}