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Formulas/physics/Kinematics/Average Acceleration

Average Acceleration

Change in velocity per unit time over a finite interval.
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Derivation

What this formula says

Over a time interval from t1t_1 to t2t_2, a body's velocity changes from v1v_1 to v2v_2. The average acceleration over this interval is:

aˉ=v2v1t2t1=ΔvΔt\bar{a} = \frac{v_2 - v_1}{t_2 - t_1} = \frac{\Delta v}{\Delta t}

It measures how much the velocity changed per unit time, on average, over that interval.

Acceleration is about velocity change — not speed change

Acceleration is the rate of change of velocity, not speed. Since velocity is a vector (it has direction), acceleration occurs whenever:

  • The speed changes (body speeds up or slows down), or
  • The direction changes (body turns), or
  • Both change simultaneously

A car turning a corner at constant speed is still accelerating — its direction is changing so its velocity vector is changing.

Derivation

This is a definition. Average acceleration is defined as:

aˉ=ΔvΔt=v2v1t2t1\bar{a} = \frac{\Delta v}{\Delta t} = \frac{v_2 - v_1}{t_2 - t_1}

where Δv=v2v1\Delta v = v_2 - v_1 is the change in velocity and Δt=t2t1\Delta t = t_2 - t_1 is the time elapsed.

Sign of average acceleration

  • aˉ>0\bar{a} > 0: velocity increased (or changed in the positive direction)
  • aˉ<0\bar{a} < 0: velocity decreased (deceleration, or retardation)
  • aˉ=0\bar{a} = 0: velocity did not change — uniform motion

Important: Negative acceleration does not always mean the body is slowing down. If a body moves in the negative direction and aˉ\bar{a} is also negative, the body is speeding up (in the negative direction).

vvaaWhat is happening
++++Moving right, speeding up
++-Moving right, slowing down
--Moving left, speeding up
-++Moving left, slowing down

The body slows down when vv and aa have opposite signs. It speeds up when they have the same sign.

Units

[a]=[v][t]=m/ss=m/s2[a] = \frac{[v]}{[t]} = \frac{\text{m/s}}{\text{s}} = \text{m/s}^2

Relation to instantaneous acceleration

Average acceleration gives the overall change. As the time interval Δt\Delta t shrinks to zero, average acceleration approaches the instantaneous acceleration at that moment:

a=limΔt0ΔvΔt=dvdta = \lim_{\Delta t \to 0} \frac{\Delta v}{\Delta t} = \frac{dv}{dt}

For uniform acceleration, average acceleration equals instantaneous acceleration at every point — they are the same constant value throughout.

Note
The equations of motion ($v = u + at$, etc.) use instantaneous acceleration $a$, which must be constant. They are not valid if $a$ varies with time. Average acceleration over an interval is a different quantity and cannot be substituted into the equations of motion.