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Formulas/physics/Kinematics/Velocity Components of a Projectile

Velocity Components of a Projectile

Horizontal and vertical velocity components at any time t.
Class 11Class JEE
Derivation

The key principle

Projectile motion is two completely independent motions happening simultaneously:

  • Horizontal: no force acts horizontally (ignoring air resistance), so horizontal velocity never changes
  • Vertical: gravity acts downward at g=9.8g = 9.8 m/s², so vertical velocity changes continuously

This independence is the foundation of all projectile motion analysis. The horizontal and vertical components never affect each other.

Setting up

A projectile is launched from the origin with speed uu at angle θ\theta above the horizontal.

The initial velocity has two components:

ux=ucosθ(horizontal)u_x = u\cos\theta \quad \text{(horizontal)} uy=usinθ(vertical, upward)u_y = u\sin\theta \quad \text{(vertical, upward)}

Derivation

Horizontal component:

No horizontal force acts, so horizontal acceleration is zero. By the first equation of motion with a=0a = 0:

vx=ux+0tv_x = u_x + 0 \cdot t

vx=ucosθ\boxed{v_x = u\cos\theta}

The horizontal velocity is constant throughout the flight. It is the same at launch, at the top, and at landing.

Vertical component:

Gravity acts downward. Taking upward as positive, vertical acceleration is g-g.

By the first equation of motion:

vy=uy+(g)tv_y = u_y + (-g)t

vy=usinθgt\boxed{v_y = u\sin\theta - gt}

The vertical velocity starts at usinθu\sin\theta (upward), decreases at rate gg, becomes zero at the top, then becomes negative (downward) on the way down.

How the vertical component changes through the flight

Momentvyv_y
At launchusinθu\sin\theta (upward)
Going upDecreasing — gravity opposes motion
At the top00 — momentarily no vertical motion
Coming downIncreasing in magnitude downward
At landingusinθ-u\sin\theta — equal and opposite to launch (by symmetry)

What stays constant, what changes

ComponentConstant or changing?Why
vx=ucosθv_x = u\cos\thetaConstantNo horizontal force
vy=usinθgtv_y = u\sin\theta - gtChangesGravity acts vertically
Key Idea
The horizontal component is constant — this is the most important single fact in projectile motion. It is what makes the trajectory a parabola rather than some other curve.
Remember
At the highest point: $v_y = 0$ but $v_x = u\cos\theta \neq 0$. The projectile is still moving horizontally. Its speed is at a minimum but not zero (unless $\theta = 90°$).