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Formulas/physics/Kinematics/Velocity Components of a Projectile

Velocity Components of a Projectile

Horizontal and vertical velocity components at any time t.
Class 11Class JEE
Derivation

The key principle

Projectile motion is two completely independent motions happening simultaneously:

  • Horizontal: no force acts horizontally (ignoring air resistance), so horizontal velocity never changes
  • Vertical: gravity acts downward at g=9.8g = 9.8 m/s², so vertical velocity changes continuously

This independence is the foundation of all projectile motion analysis. The horizontal and vertical components never affect each other.

Setting up

A projectile is launched from the origin with speed uu at angle θ\theta above the horizontal.

The initial velocity has two components:

ux=ucos⁡θ(horizontal)u_x = u\cos\theta \quad \text{(horizontal)} uy=usin⁡θ(vertical, upward)u_y = u\sin\theta \quad \text{(vertical, upward)}

Derivation

Horizontal component:

No horizontal force acts, so horizontal acceleration is zero. By the first equation of motion with a=0a = 0:

vx=ux+0⋅tv_x = u_x + 0 \cdot t

vx=ucos⁡θ\boxed{v_x = u\cos\theta}

The horizontal velocity is constant throughout the flight. It is the same at launch, at the top, and at landing.

Vertical component:

Gravity acts downward. Taking upward as positive, vertical acceleration is −g-g.

By the first equation of motion:

vy=uy+(−g)tv_y = u_y + (-g)t

vy=usin⁡θ−gt\boxed{v_y = u\sin\theta - gt}

The vertical velocity starts at usin⁡θu\sin\theta (upward), decreases at rate gg, becomes zero at the top, then becomes negative (downward) on the way down.

How the vertical component changes through the flight

Momentvyv_y
At launchusin⁡θu\sin\theta (upward)
Going upDecreasing — gravity opposes motion
At the top00 — momentarily no vertical motion
Coming downIncreasing in magnitude downward
At landing−usin⁡θ-u\sin\theta — equal and opposite to launch (by symmetry)

What stays constant, what changes

ComponentConstant or changing?Why
vx=ucos⁡θv_x = u\cos\thetaConstantNo horizontal force
vy=usin⁡θ−gtv_y = u\sin\theta - gtChangesGravity acts vertically
Key Idea
The horizontal component is constant — this is the most important single fact in projectile motion. It is what makes the trajectory a parabola rather than some other curve.
Remember
At the highest point: $v_y = 0$ but $v_x = u\cos\theta \neq 0$. The projectile is still moving horizontally. Its speed is at a minimum but not zero (unless $\theta = 90°$).