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Formulas/physics/Laws Of Motion/Centripetal Force

Centripetal Force

Force required to keep a body moving in a circular path. Directed toward the centre.
Class 11Class JEE
Derivation

What centripetal force is

A body moving in a circle is continuously changing direction. Since velocity is a vector, a change in direction is a change in velocity — even if speed is constant. Therefore a force must be acting.

This force is directed toward the centre of the circle and is called centripetal force:

Fc=mv2r=mrω2F_c = \frac{mv^2}{r} = mr\omega^2

where vv is the speed, rr is the radius, ω\omega is the angular velocity, and mm is the mass.

Derivation of centripetal acceleration

Consider a particle moving in a circle of radius rr at constant speed vv.

At time tt, velocity is v1\vec{v}_1. At time t+Δtt + \Delta t, velocity is v2\vec{v}_2. Both have magnitude vv but different directions.

The particle has moved through a small angle Δθ\Delta\theta in time Δt\Delta t.

The change in velocity Δv=v2v1\Delta\vec{v} = \vec{v}_2 - \vec{v}_1.

For small Δθ\Delta\theta, the magnitude of Δv\Delta\vec{v}:

Δv=vΔθ|\Delta\vec{v}| = v \cdot \Delta\theta

(since the velocity vector of magnitude vv has rotated by Δθ\Delta\theta)

The direction of Δv\Delta\vec{v} points toward the centre (for small Δθ\Delta\theta, the chord direction approaches the radius direction).

Acceleration:

a=limΔt0ΔvΔt=limΔt0vΔθΔt=vdθdt=vωa = \lim_{\Delta t \to 0} \frac{|\Delta\vec{v}|}{\Delta t} = \lim_{\Delta t \to 0} \frac{v \cdot \Delta\theta}{\Delta t} = v \cdot \frac{d\theta}{dt} = v\omega

Since v=rωv = r\omega:

a=vω=v2r=rω2a = v\omega = \frac{v^2}{r} = r\omega^2

This acceleration is directed toward the centre — it is called centripetal acceleration.

By Newton's Second Law:

Fc=mac=mv2r=mrω2\boxed{F_c = ma_c = \frac{mv^2}{r} = mr\omega^2}

"Centripetal force" is not a new force

This is crucial: centripetal force is not a separate type of force. It is the name given to whatever force (or combination of forces) provides the centripetal acceleration.

Circular motion situationWhat provides centripetal force
Planet orbiting the sunGravity
Car turning on a flat roadFriction (between tires and road)
Ball on a string swung in a circleString tension
Satellite in orbitGravity
Car on a banked roadNormal force component + friction
Electron in an atom (classical model)Electrostatic attraction

In each case, identify the actual physical force and set it equal to mv2r\frac{mv^2}{r}.

What centrifugal force is

In an inertial frame, there is no centrifugal force. The only real force is centripetal — toward the centre.

In a rotating (non-inertial) frame, an observer feels a pseudo force directed outward — this is called centrifugal force. It is not a real force; it is a consequence of being in a non-inertial frame.

The passenger in a car turning a corner feels pushed outward — this is the centrifugal effect. In reality, the car seat is pushing them inward (centripetal), and their inertia makes them feel the outward push relative to the car.

Effect of speed and radius

Fc=mv2rF_c = \frac{mv^2}{r}

  • Double the speed → quadruple the centripetal force needed
  • Double the radius → halve the centripetal force needed

This is why sharp turns (small rr) at high speed are dangerous — the required centripetal force grows very rapidly.

Key Idea
Never draw "centrifugal force" on a free body diagram in an inertial frame. It does not exist there. Draw the actual force providing centripetal acceleration (friction, tension, normal force component, gravity) and set its component toward the centre equal to $\frac{mv^2}{r}$.