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Impulse

Impulse equals force times time, and equals the change in momentum.
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Derivation

What impulse is

When a force acts on a body for a time Δt\Delta t, the product of force and time is called impulse:

J=FΔt\vec{J} = \vec{F} \cdot \Delta t

Impulse equals the change in momentum of the body:

J=Δp=pfpi\vec{J} = \Delta\vec{p} = \vec{p}_f - \vec{p}_i

Derivation from Newton's Second Law

From Newton's Second Law:

F=dpdt\vec{F} = \frac{d\vec{p}}{dt}

Rearrange:

dp=Fdtd\vec{p} = \vec{F} \, dt

Integrate over the time interval from t1t_1 to t2t_2:

pipfdp=t1t2Fdt\int_{\vec{p}_i}^{\vec{p}_f} d\vec{p} = \int_{t_1}^{t_2} \vec{F} \, dt

pfpi=t1t2Fdt\vec{p}_f - \vec{p}_i = \int_{t_1}^{t_2} \vec{F} \, dt

For a constant force:

Δp=FΔt=J\Delta\vec{p} = \vec{F} \cdot \Delta t = \vec{J}

Why impulse is useful

Many forces in nature act for a very short time — a bat hitting a ball, a hammer hitting a nail, a collision between cars. During these brief contacts, the force varies rapidly and is difficult to measure at every instant.

But the total effect — the change in momentum — is measurable. Impulse lets us relate the overall change in momentum to the average force without needing to know the force at every instant.

Favg=ΔpΔt\vec{F}_{avg} = \frac{\Delta\vec{p}}{\Delta t}

The impulse-momentum theorem

J=Δp\vec{J} = \Delta\vec{p}

This is the impulse-momentum theorem. It says: the impulse delivered to a body equals the change in momentum of that body. It follows directly from Newton's Second Law integrated over time.

Variable force — area under F-t graph

When force varies with time, the impulse is the area under the force-time graph:

J=t1t2F(t)dt\vec{J} = \int_{t_1}^{t_2} \vec{F}(t) \, dt

For a constant force, this is simply a rectangle: J=FΔtJ = F \cdot \Delta t.

For a varying force (like during a collision), the area under the curve gives the total impulse.

The trade-off between force and time

Since J=FΔt=ΔpJ = F \cdot \Delta t = \Delta p is fixed (the momentum change is determined by the situation), a longer contact time means a smaller average force.

This is the physics behind:

  • Airbags: increase the collision time → reduce the peak force on the passenger
  • Catching a cricket ball: pull your hands back as you catch → increase time of contact → reduce force on hands
  • Gymnastics mats: increase time of impact with the floor → reduce force on the gymnast
  • Car crumple zones: designed to increase collision time → reduce peak deceleration force

Conversely, a shorter time for the same momentum change means a larger force — this is why a karate chop delivers more force than a slow push of the same momentum change.

Units

[J]=Ns=kgm/s[J] = \text{N} \cdot \text{s} = \text{kg} \cdot \text{m/s}

Same as momentum — consistent with J=ΔpJ = \Delta p.

Remember
In problems where force is not constant but duration is very short (like a collision), always use $J = \Delta p$ to find the average force: $F_{avg} = \frac{\Delta p}{\Delta t}$. Do not try to use $F = ma$ unless you know the acceleration at every instant.