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Formulas/physics/Moving Charges/Magnetic Moment of Current Loop

Magnetic Moment of Current Loop

Magnetic dipole moment for a planar loop of N turns, area A, carrying current I. Direction n̂ along the axis by right-hand rule. SI unit: A·m².
Class 12
Derivation

Definition

For a planar loop of NN turns, area AA, carrying current II:

m=NIAn^\boxed{\vec{m} = NIA\,\hat{n}}

n^\hat{n} is the unit normal to the plane of the loop, given by the right-hand rule applied to the current direction.

SI Unit

[m]=A⋅m2[m] = \text{A·m}^2

Why This Form

The magnetic moment captures how strongly the loop interacts with an external field. From mc19, torque τ=mBsinθ\tau = mB\sin\theta — a larger mm means a stronger aligning torque for the same field.

Analogy with Electric Dipole

Electric dipoleMagnetic dipole
Momentp=qd\vec{p} = q\vec{d}m=NIAn^\vec{m} = NIA\hat{n}
Torque in fieldp×E\vec{p} \times \vec{E}m×B\vec{m} \times \vec{B}
PE in fieldpE-\vec{p}\cdot\vec{E}mB-\vec{m}\cdot\vec{B}

Far-Field Behaviour

At large distances along the axis (xRx \gg R), a current loop produces the same field as a magnetic dipole with moment m=IπR2m = I\pi R^2:

Baxisμ04π2mx3B_{\text{axis}} \approx \frac{\mu_0}{4\pi}\frac{2m}{x^3}