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Formulas/physics/Moving Charges/Galvanometer Deflection

Galvanometer Deflection

α is deflection angle; k is torsional constant of the spring. At equilibrium, magnetic torque equals restoring torque. Deflection is proportional to current — galvanometer is a linear instrument.
Class 12
Derivation

Construction

A rectangular coil of NN turns and area AA is suspended in a radial magnetic field BB (maintained by cylindrical pole pieces + soft iron core). A phosphor-bronze spring provides restoring torque.

Working

Current II through the coil → magnetic torque from mc19:

τmag=NBIA\tau_{\text{mag}} = NBIA

The radial field ensures sinθ=1\sin\theta = 1 for all deflection angles — torque is constant regardless of orientation.

At equilibrium, magnetic torque = spring restoring torque kαk\alpha:

NBIA=kαNBIA = k\alpha α=NBIAk\boxed{\alpha = \frac{NBIA}{k}}

α\alpha is the deflection angle, kk is the torsional constant of the spring.

Linearity

Since αI\alpha \propto I, the galvanometer scale is linear — equal angular divisions correspond to equal current increments.

Current Sensitivity

SI=αI=NBAkS_I = \frac{\alpha}{I} = \frac{NBA}{k}

Increased by: larger NN, stronger BB, larger area AA, weaker spring kk.

Voltage Sensitivity

SV=αV=SIG=NBAkGS_V = \frac{\alpha}{V} = \frac{S_I}{G} = \frac{NBA}{kG}

where GG is the galvanometer's own resistance.

Note
Increasing $N$ raises current sensitivity but also raises $G$, which may reduce voltage sensitivity. These two cannot be independently optimised.