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Work Done by Non-Conservative Forces

Non-conservative forces change the total mechanical energy of the system.
Class 11Class JEE
Derivation

The general energy equation

When both conservative and non-conservative forces act:

Wnc=ΔEmech=ΔKE+ΔPEW_{nc} = \Delta E_{mech} = \Delta KE + \Delta PE

Work done by non-conservative forces equals the change in total mechanical energy.

Derivation

Work-energy theorem (all forces):

Wnet=ΔKEW_{net} = \Delta KE

Split into conservative and non-conservative:

Wc+Wnc=ΔKEW_c + W_{nc} = \Delta KE

Work done by conservative forces = ΔPE-\Delta PE:

ΔPE+Wnc=ΔKE-\Delta PE + W_{nc} = \Delta KE

Wnc=ΔKE+ΔPE=ΔEmechW_{nc} = \Delta KE + \Delta PE = \Delta E_{mech}

Friction — the most common non-conservative force

Friction always does negative work: Wfriction=fkdW_{friction} = -f_k \cdot d

fkd=ΔKE+ΔPE-f_k d = \Delta KE + \Delta PE

Emech,f=Emech,ifkdE_{mech,f} = E_{mech,i} - f_k d

Mechanical energy decreases by exactly the magnitude of work done by friction. This energy goes into heat.

Example: A block slides down a rough incline of height hh and length ll, friction coefficient μ\mu:

Wnc=μmgcosθlW_{nc} = -\mu mg\cos\theta \cdot l

12mv2mgh=μmglcosθ\frac{1}{2}mv^2 - mgh = -\mu mgl\cos\theta

v=2gh2μglcosθ=2gl(sinθμcosθ)v = \sqrt{2gh - 2\mu gl\cos\theta} = \sqrt{2gl(\sin\theta - \mu\cos\theta)}

Consistent with the kinematics result v2=2asv^2 = 2as with a=g(sinθμcosθ)a = g(\sin\theta - \mu\cos\theta).

When Wnc>0W_{nc} > 0

An external engine or motor does positive work on the system — mechanical energy increases. A car engine converts chemical energy (fuel) to mechanical energy.

Energy accounting

Non-conservative forces do not destroy energy — they convert mechanical energy into other forms:

  • Friction → heat
  • Air resistance → heat + sound
  • Inelastic collision → heat + deformation energy
  • Motor → mechanical energy (from electrical/chemical)

Total energy (all forms) is always conserved. Wnc=ΔEmechW_{nc} = \Delta E_{mech} just tracks what enters or leaves the mechanical energy "account".

Remember
Problem strategy: if friction is present, use $W_{nc} = \Delta E_{mech}$ rather than conservation of mechanical energy. Calculate $W_{friction} = -f_k \cdot d$ (always negative) and set it equal to $\frac{1}{2}mv_f^2 + mgh_f - \frac{1}{2}mv_i^2 - mgh_i$.