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Formulas/physics/Rotational Motion/Moment of Inertia — Definition

Moment of Inertia — Definition

Moment of inertia is the rotational analogue of mass. Measures resistance to angular acceleration.
Class 11Class JEE
Derivation

What moment of inertia is

In linear motion, mass measures resistance to acceleration: a=F/ma = F/m.

In rotational motion, the corresponding quantity is moment of inertia II: α=τ/I\alpha = \tau/I.

A body with larger II is harder to spin up or slow down — it has more rotational inertia.

For a system of point masses:

I=miri2I = \sum m_i r_i^2

For a continuous body:

I=r2dmI = \int r^2 \, dm

where rr is the perpendicular distance of each mass element from the rotation axis.

Why r2r^2 and not rr?

The r2r^2 dependence comes from the dynamics. Consider a point mass mm at distance rr from the axis, pulled by tangential force FtF_t:

Ft=mat=m(rα)F_t = ma_t = m(r\alpha)

Torque: τ=Ftr=mr2α\tau = F_t \cdot r = mr^2\alpha

So: τ=(mr2)α\tau = (mr^2)\alpha

The quantity mr2mr^2 is the moment of inertia — the coefficient relating torque to angular acceleration for a single particle.

For a system: τ=miri2α=Iα\tau = \sum m_i r_i^2 \cdot \alpha = I\alpha

Key properties

II depends on the axis. The same body has different moments of inertia about different axes. Always specify the axis.

II depends on mass distribution, not just total mass. Two bodies of equal mass can have very different II if mass is distributed differently relative to the axis.

Mass farther from axis contributes more. Due to r2r^2, mass at distance 2r2r contributes 4 times as much as mass at distance rr.

Units

[I]=kgm2[I] = \text{kg} \cdot \text{m}^2

Radius of gyration kk

The radius of gyration kk is defined by:

I=Mk2    k=IMI = Mk^2 \implies k = \sqrt{\frac{I}{M}}

kk is the distance from the axis at which all the mass could be concentrated to give the same moment of inertia. It characterises the "effective" radius of the mass distribution.

BodyAxisIIkk
RingCentral, perpendicularMR2MR^2RR
DiscCentral, perpendicular12MR2\frac{1}{2}MR^2R2\frac{R}{\sqrt{2}}
Solid sphereDiameter25MR2\frac{2}{5}MR^2R2/5R\sqrt{2/5}
Hollow sphereDiameter23MR2\frac{2}{3}MR^2R2/3R\sqrt{2/3}
Key Idea
$I$ is not a fixed property of a body — it depends on which axis you choose. When a problem asks for "the moment of inertia", always check which axis is specified. The same disc has $\frac{1}{2}MR^2$ about its central perpendicular axis but $\frac{1}{4}MR^2$ about a diameter.