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PhysicsOscillationsShmEnergy in Simple Harmonic Motion

Energy in Simple Harmonic Motion

Kinetic and potential energy in SHM — their exchange, their sum, and why total energy depends only on amplitude.

Energy is never destroyed in SHM — it perpetually converts between kinetic and potential form. The total stays constant.

The energy exchange

Watch KE and PE trade places as the block oscillates. Their sum — total energy E — never changes:

SpringMass amplitude 80 k 100 m 1
Show spring block wall energy KE PE E graph-x
Hide readouts displacement-arrow velocity-arrow acceleration-arrow equilibrium

Green bar = KE. Orange bar = PE. Blue bar = total E (always full).

All PE at the extremes

Block at x=+Ax = +A. Spring fully stretched. All energy is stored as potential energy. KE is zero — the block has momentarily stopped:

SpringMass amplitude 80 k 100 m 1
Snapshot at extreme
Show spring block wall displacement-arrow energy KE PE E
Hide graph-x readouts velocity-arrow acceleration-arrow equilibrium

PEmax=12kA2,KE=0PE_{max} = \frac{1}{2}kA^2, \quad KE = 0

All KE at the centre

Block passes through equilibrium. Spring at natural length — zero PE. All energy is kinetic. This is where the block moves fastest:

SpringMass amplitude 80 k 100 m 1
Snapshot at centre
Show spring block wall velocity-arrow energy KE PE E
Hide graph-x readouts displacement-arrow acceleration-arrow equilibrium

KEmax=12kA2,PE=0KE_{max} = \frac{1}{2}kA^2, \quad PE = 0

KE = PE at x=A/2x = A/\sqrt{2}

There is a precise position where kinetic and potential energy are exactly equal — each is half the total:

SpringMass amplitude 80 k 100 m 1
Snapshot at equal-energy
Show spring block wall displacement-arrow energy KE PE E
Hide graph-x readouts velocity-arrow acceleration-arrow equilibrium

KE=PE=E2atx=±A2KE = PE = \frac{E}{2} \quad \text{at} \quad x = \pm\frac{A}{\sqrt{2}}

Energy vs displacement

The PE curve is a parabola. KE is the gap between PE and total energy E. The position marker (white line) shows where the block currently is:

SpringMass amplitude 80 k 100 m 1
Snapshot at equal-energy
Show spring block wall graph-energy KE PE E
Hide energy readouts displacement-arrow velocity-arrow acceleration-arrow equilibrium

The formulas

KE=12mv2=12k(A2x2)KE = \frac{1}{2}m v^2 = \frac{1}{2}k(A^2 - x^2)

PE=12kx2PE = \frac{1}{2}kx^2

E=KE+PE=12kA2(constant)\boxed{E = KE + PE = \frac{1}{2}kA^2 \quad \text{(constant)}}

Total energy depends only on kk and amplitude. Not on position. Not on time. Doubling the amplitude quadruples the total energy (EA2E \propto A^2).