Academy
PhysicsOscillationsShmThe Spring-Mass System

The Spring-Mass System

How spring constant k and mass m determine the time period — and what changes when springs are combined.

The spring-mass system is the prototype of SHM. Every result here applies — with appropriate substitution — to pendulums, LC circuits, and molecular vibrations.

The time period

Newton's second law + Hooke's law:

mx¨=kx    ω=km,T=2πmkm\ddot{x} = -kx \implies \omega = \sqrt{\frac{k}{m}}, \quad \boxed{T = 2\pi\sqrt{\frac{m}{k}}}

Heavier mass → slower oscillation

TmT \propto \sqrt{m}. Quadrupling mass doubles the period.

Light mass (m=1m = 1 kg):

SpringMass amplitude 60 k 100 m 1
Show spring block wall graph-x readouts
Hide energy displacement-arrow velocity-arrow acceleration-arrow equilibrium

Heavy mass (m=4m = 4 kg, same spring):

SpringMass amplitude 60 k 100 m 4
Show spring block wall graph-x readouts
Hide energy displacement-arrow velocity-arrow acceleration-arrow equilibrium

Watch the x(t) graph — cycles are twice as wide. T displayed in the readout confirms it.

Stiffer spring → faster oscillation

T1/kT \propto 1/\sqrt{k}. Quadrupling stiffness halves the period.

Soft spring (k=50k = 50 N/m):

SpringMass amplitude 60 k 50 m 1
Show spring block wall graph-x readouts
Hide energy displacement-arrow velocity-arrow acceleration-arrow equilibrium

Stiff spring (k=200k = 200 N/m, same mass):

SpringMass amplitude 60 k 200 m 1
Show spring block wall graph-x readouts
Hide energy displacement-arrow velocity-arrow acceleration-arrow equilibrium

Springs in series

Two springs end-to-end. Same force stretches both — displacements add:

1keff=1k1+1k2    keff=k1k2k1+k2\frac{1}{k_{eff}} = \frac{1}{k_1} + \frac{1}{k_2} \implies k_{eff} = \frac{k_1 k_2}{k_1 + k_2}

Effective stiffness is less than either spring. Period is longer.

Springs in parallel

Two springs side by side. Same displacement — forces add:

keff=k1+k2k_{eff} = k_1 + k_2

Effective stiffness is greater. Period is shorter.

Cutting a spring

A spring of constant kk cut to 1n\frac{1}{n} of its length has constant nknk.

Fewer coils → each coil must stretch more per unit force → stiffer.

Configurationkeffk_{eff}TT
Single kkkk2πm/k2\pi\sqrt{m/k}
Series k1,k2k_1, k_2k1k2k1+k2\frac{k_1 k_2}{k_1+k_2}longer
Parallel k1,k2k_1, k_2k1+k2k_1 + k_2shorter
Cut to 1/n1/nnknkT/nT/\sqrt{n}